71. A number exceeds another number by 5, the sum of the numbers is 19. Find the smaller number. #SU Sindh University jamshoro Entry test Paper 2024 Phase I (sindh university jamshoro admission Entry test Paper 2024)

PART-IV (SIMPLE ARITHMETIC) 

71. A number exceeds another number by 5, the sum of the numbers is 19. Find the smaller number.

 (A) 5 (C) 7 (B) 6   (D) 12

Solution  :    LET ONE NUMBER BE "X" THEN THE OTHER ARE ' X+5'

TAKING THE EQUESTION IS  

X+X+5=19

2X+5=19

2X=19-5

2X=14

X=14/2

              X=7     IS             

 SMALLER NUMBER

X+5=?

(7)+5=12

LARGER NUMER IS 12